Diagonal Difference - Hacker Rank Solution

Given a square matrix of size N×N, calculate the absolute difference between the sums of its diagonals.

Input Format

The first line contains a single integer, N. The next N lines denote the matrix's rows, with each line
containing N space-separated integers describing the columns.

Output Format

Print the absolute difference between the two sums of the matrix's diagonals as a single integer.

Sample Input

3
11 2 4
4 5 6
10 8 -12

Sample Output

15

Explanation

The primary diagonal is:
11
      5
            -12
Sum across the primary diagonal: 11 + 5 - 12 = 4
The secondary diagonal is:
            4
      5
10
Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 - 19| = 15
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  Diagonal Difference - Hacker Rank Solution 

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main()
{
    int a[100][100],n,c=0,d=0,i,j,sum=0;
    scanf("%d",&n);
    for(i=0;i<n;i++)
        for(j=0;j<n;j++)
            scanf("%d",&a[i][j]);
    for(i=0;i<n;i++)
         c=c+a[i][i];        
    for(i=0;i<n;i++)
         d=d+a[i][n-1-i];
    sum=abs(c-d);
    printf("%d",sum);
          
  
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */  
    return 0;
}

 Diagonal Difference - Hacker Rank Solution 

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