Given the names and grades for each student in a Physics class of students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade.
Note: If there are multiple students with the same grade, order their names alphabetically and print each name on a new line.
Input Format
The first line contains an integer, , the number of students.
The subsequent lines describe each student over lines; the first line contains a student's name, and the second line contains their grade.
The subsequent lines describe each student over lines; the first line contains a student's name, and the second line contains their grade.
Constraints
- There will always be one or more students having the second lowest grade.
Output Format
Print the name(s) of any student(s) having the second lowest grade in Physics; if there are multiple students, order their names alphabetically and print each one on a new line.
Sample Input 0
5
Harry
37.21
Berry
37.21
Tina
37.2
Akriti
41
Harsh
39
Sample Output 0
Berry
Harry
Explanation 0
There are students in this class whose names and grades are assembled to build the following list:
python students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], ['Harsh', 39]]
The lowest grade of belongs to Tina. The second lowest grade of belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line.
Nested Lists - Hacker Rank Solution
We can solve this challenge by using nested list.
Problem Setter's code:
from __future__ import print_function
score_list = {}
for _ in range(input()):
name = raw_input()
score = float(raw_input())
if score in score_list:
score_list[score].append(name)
else:
score_list[score] = [name]
new_list = []
for i in score_list:
new_list.append([i, score_list[i]])
new_list.sort()
result = new_list[1][1]
result.sort()
print (*result, sep = "\n")
Problem Tester's code:
a = [[raw_input(), float(raw_input())] for i in xrange(int(raw_input()))]
s = sorted(set([x[1] for x in a]))
for name in sorted(x[0] for x in a if x[1] == s[1]):
print name
its showing list index out of range error
ReplyDeletetrendingz.com
ReplyDeleteN = int(input())
ReplyDeletelist = []
num = []
nl = []
for i in range(0,N):
a = input()
b = float(input())
num.append(b)
list.append([a,b])
#print(list)
#print(num)
num.sort()
num.reverse()
#print(num)
c = num.count(min(num))
number=num[len(num)-c-1]
#print(number)
for i in range(0,N):
if(number==list[i][1]):
#print(list[i][0])
nl.append(list[i][0])
nl.sort()
#print(nl)
for x in range(len(nl)):
print (nl[x])
can u explain the problem setter code...
ReplyDeletewhich is mentioned above.