In this task, we would like for you to appreciate the usefulness of the groupby() function of itertools . To read more about this function, Check this out .
You are given a string . Suppose a character '' occurs consecutively times in the string. Replace these consecutive occurrences of the character '' with in the string.
For a better understanding of the problem, check the explanation.
Input Format
A single line of input consisting of the string .
Output Format
A single line of output consisting of the modified string.
Constraints
All the characters of denote integers between and .
Sample Input
1222311
Sample Output
(1, 1) (3, 2) (1, 3) (2, 1)
Explanation
First, the character occurs only once. It is replaced by . Then the character occurs three times, and it is replaced by and so on.
Also, note the single space within each compression and between the compressions.
Compress the String! - Hacker Rank Solution
from __future__ import print_function from itertools import * for i,j in groupby(map(int,list(raw_input()))): print(tuple([len(list(j)), i]) ,end = " ")
from itertools import groupby
ReplyDeletea=(input())
z=[]
b=[tuple(g) for k,g in groupby(a)]
for i in range(len(b)):
x=str(len(b[i]))
if len(b[i]):
y=str(b[i][0])
else:
y=str(b[i])
z.append("("+x+", "+y+")")
print(" ".join(z))